Asked by slomo
Find the quotient
6s^7p^8-6s^5p^6+27s^3p^4
_________________________
3s^3p
Please help, I am lost on this process
6s^7p^8-6s^5p^6+27s^3p^4
_________________________
3s^3p
Please help, I am lost on this process
Answers
Answered by
Steve
just divide each term, then add them up:
6s^7p^8/3s^3p = 6/3 s^7/s^3 p^8/p = 2s^4p^7
6s^5p^6/3s^3p = 2s^2p^5
27s^3p^4/2s^3p = 9p^3
So, the final sum is
2s^4p^7 - 2s^2p^5 + 9p^3
6s^7p^8/3s^3p = 6/3 s^7/s^3 p^8/p = 2s^4p^7
6s^5p^6/3s^3p = 2s^2p^5
27s^3p^4/2s^3p = 9p^3
So, the final sum is
2s^4p^7 - 2s^2p^5 + 9p^3
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