Asked by COFFEE
Two horizontal forces act on a 2.4 kg chopping block that can slide over a frictionless kitchen counter, which lies in an xy plane. One force is F1 = (3.4 N) i + (3.7 N) j. Find the acceleration of the chopping block in unit-vector notation for each of the following second forces:
F2 = (-3.4 N) i + (-3.7 N) j
F2 = (-3.4 N) i + (3.7 N) j
F2 = (3.4 N) i + (-3.7 N) j
In vector notation;
Force= mass*acceleration
acceleration= Force/mass
add the vector forces, divide bymass
example, the last:
Ftotal=F1 + F2
= 3.4 i + 3.7 j + 3.4i - 3.7 j
= 6.8 i
acceleration= 6.8/2.4 i
F2 = (-3.4 N) i + (-3.7 N) j
F2 = (-3.4 N) i + (3.7 N) j
F2 = (3.4 N) i + (-3.7 N) j
In vector notation;
Force= mass*acceleration
acceleration= Force/mass
add the vector forces, divide bymass
example, the last:
Ftotal=F1 + F2
= 3.4 i + 3.7 j + 3.4i - 3.7 j
= 6.8 i
acceleration= 6.8/2.4 i
Answers
Answered by
Anonymous
a = (F1 + F2) / m
where a, F1, & F2 are in vector notation
where a, F1, & F2 are in vector notation
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.