Asked by Louis
Find all solutions of the equation in the interval [0, 2pi). Show all work.
sin(x+(pi/6))-sin(x-((pi/6))=1/2
sin(x+(pi/6))-sin(x-((pi/6))=1/2
Answers
Answered by
Steve
using the difference formula, you have
sin(x)cos(π/6)+cos(x)sin(π/6) - sin(x)sin(π/6)+cos(x)sin(π/6) = 1/2
2cos(x)sin(π/6) = 1/2
2cos(x)(1/2) = 1/2
cos(x) = 1/2
x = π/3 or 5π/3
http://www.wolframalpha.com/input/?i=sin%28x%2B%28pi%2F6%29%29-sin%28x-%28pi%2F6%29%29%3D1%2F2+for+x+%3D+0+to+2pi
sin(x)cos(π/6)+cos(x)sin(π/6) - sin(x)sin(π/6)+cos(x)sin(π/6) = 1/2
2cos(x)sin(π/6) = 1/2
2cos(x)(1/2) = 1/2
cos(x) = 1/2
x = π/3 or 5π/3
http://www.wolframalpha.com/input/?i=sin%28x%2B%28pi%2F6%29%29-sin%28x-%28pi%2F6%29%29%3D1%2F2+for+x+%3D+0+to+2pi
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