Asked by unknown
The U.S. five-cent coin, the nickel, has a mass of 5.1 g, a volume of 0.719 cm3, and a total surface area of 8.54 cm2. Assuming that a nickel is an ideal radiator, how much radiant energy per second comes from the nickel, if it is at 24∘C?
Answers
Answered by
GoldenHawk
use the equation P = AoT^4
where P is Q/t
A is surface area
"o" is actually the greek letter for Stefan Boltzman constant :
5.67x10^(-8) J/s*m^2*K^4
* not greek letters on keyboard lol
and T is temperature in kelvin
DON'T FORGET TO CONVERT YOUR UNITS
You should get:
P= A o T^4
P = (8.54x10^(-4))(5.67x10^(-8))(24+273)^4
A is 8.54x10^(-4) because you have to convert cm^2 to m^2 because of the units for Boltzman's constant
where P is Q/t
A is surface area
"o" is actually the greek letter for Stefan Boltzman constant :
5.67x10^(-8) J/s*m^2*K^4
* not greek letters on keyboard lol
and T is temperature in kelvin
DON'T FORGET TO CONVERT YOUR UNITS
You should get:
P= A o T^4
P = (8.54x10^(-4))(5.67x10^(-8))(24+273)^4
A is 8.54x10^(-4) because you have to convert cm^2 to m^2 because of the units for Boltzman's constant
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.