Asked by Aaqib zaman
The length, l mm of an elastic string at time t seconds is given by
l=t^3 / 3 - 4t +10
Find the instants (that is, the value of t ) when
a) The length is increasing at a rate of 5 mm/Sec
b) The length is decreasing at a rate of 4 mm/Sec
l=t^3 / 3 - 4t +10
Find the instants (that is, the value of t ) when
a) The length is increasing at a rate of 5 mm/Sec
b) The length is decreasing at a rate of 4 mm/Sec
Answers
Answered by
ms lina
l'= t^2-4
5=t^2-4
5+4=t^4
9=t^2
t=root 9
t=3
5=t^2-4
5+4=t^4
9=t^2
t=root 9
t=3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.