Asked by Aaqib zaman

The length, l mm of an elastic string at time t seconds is given by
l=t^3 / 3 - 4t +10

Find the instants (that is, the value of t ) when
a) The length is increasing at a rate of 5 mm/Sec
b) The length is decreasing at a rate of 4 mm/Sec

Answers

Answered by ms lina
l'= t^2-4
5=t^2-4
5+4=t^4
9=t^2
t=root 9
t=3
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