Ask a New Question
Search
Asked by
Bear
Prove the identity
(sinx+cosx)^2 = 1+sin2x
Thank you
Answers
Answers
Answered by
Steve
(sinx+cosx)^2 = sin^2 x + 2 sinx cosx + cos^2 x
now recall the most fundamental of your trig identities, and the double-angle formulas.
Related Questions
Related
prove the identity (sinX)^6 +(cosX)^6= 1 - 3(sinX)^2 (cosX)^2 sinX^6= sinx^2 ^3 = (1-cosX^2)^3...
Establish the identity. sinx + cosx/sinx - cosx = 1+2sinxcosx/2sin^2x-1
prove 1/sinx-sinx=cos^2xcscx
Proving identity (sinx+tanx)/(cosx+1)=tanx RS: (sinx+(sinx/cosx))/(cosx+1) ((sinxcosx/cosx)+(sinx...
verify identity (sinx-cosx)^2=1-sin(2x)
prove identity Sin2x - sinx/cosx + cos2x= sinx/cosx + 1
Prove that (1+sinx-cosx/1+sinx+cosx)^2= 1-cosx/1+cosx
Prove the identity 2 - (sinx + cosx)² = (sinx - cosx)²
Complete the identity sinx/cosx+cosx/sinx=?
Complete the identity (sinx+cosx)^2/1+2sinxcosx=? A. 1-sinx B. -sec^2x C. 0 D. 1