Asked by Francis
Find ¡Ò[dx/(x-2)(x+3)(x-4)]
this is really confusing and I need help with it.
this is really confusing and I need help with it.
Answers
Answered by
Steve
use partial fractions:
1/((x-2)(x+3)(x-4)) =
-1/10(x-2) + 1/35(x+3) + 1/14(x-4)
Now it's just a bunch of simple logs.
1/((x-2)(x+3)(x-4)) =
-1/10(x-2) + 1/35(x+3) + 1/14(x-4)
Now it's just a bunch of simple logs.
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