Question

A rock is dropped off the edge of the cliff and its distance S ( in feet ) from the top of the cliff after T seconds is S ( T ) = 16t^2. Assume the distance from the top ofthe cliff to the water below is 96ft

Make a table of the average velocity and approximate the velocity at which the rock strikes the water?

Answer 1

the rock hits in √6 seconds. My table is

t v (at)
0 0
√6 32√6
avg speed: 32√6/√6 = 32

t s (1/2 at^2)
0 0
√6 96
avg speed: 96/√6 = 16√6

Ya gotta be specific to get what you want.

Answer 2

Thank you that was the exact question. I wish it was more specific