Asked by Anonymous
                dy/dx=x+y, y(0)=1
How do I solve for y(x)?
I know the answer is y(x)=2e^x-x-1, but I forgot how to do these kinds of problems again.
            
        How do I solve for y(x)?
I know the answer is y(x)=2e^x-x-1, but I forgot how to do these kinds of problems again.
Answers
                    Answered by
            bobpursley
            
    This is and ordinary differential equation with exact roots.
What I suggest to review these is to go to Barnes Noble, or any good bookstore, and purchase Schaum's Outline Series, Differential Equations, an excellent book and buy. Take a look.
There is an abridged version online
http://www.ebookmall.com/ebook/133885-ebook.htm
But, I would be wary of abridging a condensed study guide.
Good luck.
    
What I suggest to review these is to go to Barnes Noble, or any good bookstore, and purchase Schaum's Outline Series, Differential Equations, an excellent book and buy. Take a look.
There is an abridged version online
http://www.ebookmall.com/ebook/133885-ebook.htm
But, I would be wary of abridging a condensed study guide.
Good luck.
                    Answered by
            drwls
            
    This is a first order linear differential equation and can be solved by the "integrating factor" method. 
See http://www.sosmath.com/diffeq/first/lineareq/lineareq.html
    
See http://www.sosmath.com/diffeq/first/lineareq/lineareq.html
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