Question

A bicycle wheel has a diameter of 47.6 cm and a mass of 0.809 kg. The bicycle is placed on a stationary stand on rollers and a resistive force of 60.1 N is applied to the rim of the tire. Assume all the mass of the wheel is concentrated on the outside radius.
In order to give the wheel an acceleration of 3.18 rad/s2, what force must be applied by a chain passing over a sprocket with diameter 4.16 cm?
Answer in units of N.

Moment of inertia of the wheel is I=MR^2
From resistance force=-force*R

Answer 1

net torque= momentInertia*angular acceleration

a. figure the moment of inertia for the wheel.
b. Net torque= force*.0416/2-60.1*.476/2
c. you are given angular acceleration
figure then, force.

Answer 2

I ask you and the response is asking sorry I will never use this application.