Question
The perimeter of a rectangular piece of plastic is 22 millimeters. The area is 30 square millimeters. What are the dimensions of the piece of plastic?
Answers
Reiny
2l + 2w = 22
l + w = 11 ---> l = 11 - w
area = 30
lw = 30
(11-w)(w) = 30
11w - w^2 = 30
w^2 - 11w + 30 = 0
(w-5)(w-6) = 0
w = 5 or w = 6
if w = 5 , l = 11-5 = 6
if w = 6, l = 11 - 6 = 5
the dimension is 5 by 6 mm
l + w = 11 ---> l = 11 - w
area = 30
lw = 30
(11-w)(w) = 30
11w - w^2 = 30
w^2 - 11w + 30 = 0
(w-5)(w-6) = 0
w = 5 or w = 6
if w = 5 , l = 11-5 = 6
if w = 6, l = 11 - 6 = 5
the dimension is 5 by 6 mm
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