Asked by Alex

When iron rusts in air, iron (III) oxide is produced. How many moles of oxygen react with 7.2 mol of iron in the rusting reaction? 4Fe(s)+3O2=2Fe2O3(s)
Answered by DrBob222
Use the coefficients in the balanced equation to convert anything to anything.
7.2 mol Fe x (3 mols O2/4 mols Fe) = 7.2*3/4 = ?
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