Asked by Thandi Mstletoe
Determining the first three terms of an ArithmetiC progressionof which the (a.)10th term is 31 and the 15th term is 49 (b.)7th term is 3 and 12th term is -3 (c.)5th term is 8 and the 11th term is -28 (d.)9th term is7+9x and d=2x,Show all calculations
Answers
Answered by
Steve
(a)
a+9d = 31
a+14d = 49
d = 18/5
a = -7/5
so, we have
-7/5, 11/5, 29/5, ...
(b) and (c) are just the same.
(d)
a+8d = a+16x = 7+9x
a = 7-7x
so,
7-7x, 7-5x, 7-3x ...
a+9d = 31
a+14d = 49
d = 18/5
a = -7/5
so, we have
-7/5, 11/5, 29/5, ...
(b) and (c) are just the same.
(d)
a+8d = a+16x = 7+9x
a = 7-7x
so,
7-7x, 7-5x, 7-3x ...
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.