Question

Hi! Okay so I started to attempt this math problem; 3cot^2x-1=0. However, I'm a little stuck. My teacher wants me to find the Location on The Unit Circle, Period, and General Solution. Can someone check what I have and help me with the rest?


3cot^2x-1=0
cot^2x=1/3
tan^2x=3
tanx=+ and - sqrt3

Location: pi/3,2pi/3,4pi/3 and 5pi/3

Period: 3pi?????

General Solution: (Not sure)

Answer 1

the period of cot(x) is pi. The amplitude and power make no difference.

So, the general solutions are

n*pi ± pi/3

for any integer n.