Asked by Susan

What are the domain and range for 2(y-1)= - the square root of 1/3x-6
Answered by Tia
The domain is: [18,∞),{x|x≥18}
The range is: [0,∞),{y|y≥0}
Answered by Steve
Hmmm.

y = 1 - 1/(2√(3x-6))

I get a horizontal asymptote at y=1, with the range (-∞,1)
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