Asked by Alex
Determine if each system has one, two, or no solutions. (Show your work - 3 marks each)
a)y=2x^2-2x+1 and y=3x-5
b)y=x^2+3x-16 and y=-x^2-8x-18
a)y=2x^2-2x+1 and y=3x-5
b)y=x^2+3x-16 and y=-x^2-8x-18
Answers
Answered by
Reiny
Same thing as your last post
Just evaluate b^2 - 4ac and decide
Just evaluate b^2 - 4ac and decide
Answered by
Alex
So I use the quadratic formula?
Answered by
Reiny
You could but you don't have to
recall that
x = (-b ± √(b^2 - 4ac)/(2a)
Judging from the type of question you have been asking, I trust you have learned the properties of the "discriminant" b^2 - 4ac
I gave them to you in one of the posts.
recall that
x = (-b ± √(b^2 - 4ac)/(2a)
Judging from the type of question you have been asking, I trust you have learned the properties of the "discriminant" b^2 - 4ac
I gave them to you in one of the posts.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.