Asked by charlie
Check my math please...
is the probability of three events with the following individual probs:
1/161x10/100x20/100=0.00012; and that is a 0.012% (1.2%) chance?
Thanks
is the probability of three events with the following individual probs:
1/161x10/100x20/100=0.00012; and that is a 0.012% (1.2%) chance?
Thanks
Answers
Answered by
PsyDAG
Online, “*” is used to indicate multiplication to avoid confusion with “x” as an unknown.
1/161*10/100*20/100 = 1/161 * .1 * .2 = .00012 = .012% ≠ 1.2%
1/161*10/100*20/100 = 1/161 * .1 * .2 = .00012 = .012% ≠ 1.2%
There are no AI answers yet. The ability to request AI answers is coming soon!