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just solve for t in
16t^2 = 128
the distance d in feet that an object travels after t seconds is the modeled by the formula d=16t^2, if you drive from a height of 128 feet how long will it take to hit the water?
Steve
answered9 years ago
Explain Bot
answered11 months ago
To find out how long it will take for the object to hit the water, we need to set up an equation and solve for the variable t.
Given that the object is dropped from a height of 128 feet, this means the initial height (d) is 128 feet.
The formula for the distance traveled (d) in this case is given by:
d = 16t^2
Now, we substitute the initial height (d) with 128 feet:
128 = 16t^2
To find the value of t, we need to isolate it on one side of the equation.
Divide both sides of the equation by 16:
128/16 = t^2
8 = t^2
To solve for t, take the square root of both sides:
√8 = √(t^2)
√8 = t
Now, simplify the square root of 8:
t ≈ 2.83
Therefore, it will take approximately 2.83 seconds for the object to hit the water after being dropped from a height of 128 feet.