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just solve for t in
16t^2 = 128
16t^2 = 128
Given that the object is dropped from a height of 128 feet, this means the initial height (d) is 128 feet.
The formula for the distance traveled (d) in this case is given by:
d = 16t^2
Now, we substitute the initial height (d) with 128 feet:
128 = 16t^2
To find the value of t, we need to isolate it on one side of the equation.
Divide both sides of the equation by 16:
128/16 = t^2
8 = t^2
To solve for t, take the square root of both sides:
√8 = √(t^2)
√8 = t
Now, simplify the square root of 8:
t ≈ 2.83
Therefore, it will take approximately 2.83 seconds for the object to hit the water after being dropped from a height of 128 feet.