for what integral value(s) of K can the trinomial x^2 + kx +12 be factored?

my English is limited, I not sure what the question is asking, can everyone help me?

Thank You!

1 answer

integral values are integer numbers, so k cannot be a fraction

possible factors that end in +12:

(x+1)(x+12)
(x-1)(x-12)
(x+2)(x+6)
(x-2)(x-6)--> x^2 - 8x + 12 , so k = -8
(x+3)(x+4)
(x-3)(x-4)

I expanded one of them, to show one value of k
You do the others
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