The speed of a bullet as it travels down the barrel of a rifle toward the opening is given by v = (-4.25 107) t 2 + (3.45 105) t, where v is in meters per second and t is in seconds. The acceleration of the bullet just as it leaves the barrel is zero.

Question

The speed of a bullet as it travels down the barrel of a rifle toward the opening is given by v = (-4.25  107) t 2 + (3.45  105) t, where v is in meters per second and t is in seconds. The acceleration of the bullet just as it leaves the barrel is zero.
(a) Determine the acceleration and position of the bullet as a function of time when the bullet is in the barrel. (Use t as necessary and round all numerical coefficients to exactly 3 significant figures.)
a =	 m/s2
x =	 m

(b) Determine the length of time the bullet is accelerated.
  s

(c) Find the speed at which the bullet leaves the barrel.
  m/s

(d) What is the length of the barrel?
  m