A ball is thrown upward from the ground with an initial speed of 16.0 m/s; at the same instant, another ball is dropped from a building 12 m high. After how long will the balls be at the same height above the ground?

Answer 1

d1 + d2 = 12 m.

d1 = Vo*t + 0.5g*t^2

d2 = 0.5g*t^2

16*t - 4.9*t^2 + 4.9*t^2 = 12
16*t = 12
t = 0.75 s.

Answer 2

An object is thrown upwards at an initial speed of 19.6 m/s from a height of 40.0 m. Determine how long it will take for the object to reach the ground.