Asked by Kat
Calculate the pH and concentration of H3O+ of a 0.285M oxalic acid solution.
Answers
Answered by
DrBob222
.......H2C2O4(aq) ==> H^+ + HC2O4^-
I.......285...........0......0
C.......-x............x......x
E....0.285-x..........x......x
Substitute the E line into the Ka1 expression for H2C2O4 and solve for (H^+), then pH = -log(H^+).
I assume that the (H^+) is largely due to that contributed by Ka1 and none by Ka2. Actually, some will come from Ka2 but only about 1 in 1000 molecules that dissociate so the error will not be that large by neglecting that contribution from Ka2.
I.......285...........0......0
C.......-x............x......x
E....0.285-x..........x......x
Substitute the E line into the Ka1 expression for H2C2O4 and solve for (H^+), then pH = -log(H^+).
I assume that the (H^+) is largely due to that contributed by Ka1 and none by Ka2. Actually, some will come from Ka2 but only about 1 in 1000 molecules that dissociate so the error will not be that large by neglecting that contribution from Ka2.
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