Asked by Restoration
Determine T10 of the following geometric sequence
T2=4x and T5=x^4/8(x exponent 4 divided by 8)
T2=4x and T5=x^4/8(x exponent 4 divided by 8)
Answers
Answered by
Steve
T5/T2 = r^3, so
r^3 = (x^4/8)/(4x) = x^3/32
r = x/∛32
I suspect a typo, but we'll go with what we have.
T10 = T5 r^5 = x^4/8 * x^5/(256∛2) = x^9/(2048∛2)
r^3 = (x^4/8)/(4x) = x^3/32
r = x/∛32
I suspect a typo, but we'll go with what we have.
T10 = T5 r^5 = x^4/8 * x^5/(256∛2) = x^9/(2048∛2)
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