Question
In an arithmetic sequence the seventh term exceeds the fourth term by 15 determine the common difference
Answers
Reiny
term(7) = a+6d
term(4) = a+3d
a+6d - (a+3d) = 15
a+6d-a-3d=15
3d=15
d = 5
term(4) = a+3d
a+6d - (a+3d) = 15
a+6d-a-3d=15
3d=15
d = 5