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In an arithmetic sequence the seventh term exceeds the fourth term by 15 determine the common difference
10 years ago

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Answered by Reiny
term(7) = a+6d
term(4) = a+3d

a+6d - (a+3d) = 15
a+6d-a-3d=15
3d=15
d = 5
10 years ago
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In an arithmetic sequence the seventh term exceeds the fourth term by 15 determine the common difference

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