Question

Two small beads having positive charges q1 = 34.0 nC and q2 = 55.0 nC are fixed so that the centers of the two beads are separated by a distance d = 0.450 m as shown in the figure. At what position x relative to q1 could you place a third small bead of unknown charge q in order for it to be in equilibrium? Answer in units of meters.

Answer 1

if they are in a straight line, then the forces on q3 are balanced, that is possible to do this by placing a positive (or negative) charge q3 in between so the forces are balanced both ways.

ForceLeft=ForceRight
kq1q3/x^2=kq2q3/(.45-x)^2

(.45-x)^2= q2/q1 ( x^2)

expand all that to a quadratic, and solve for x.

Answer 2

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