Asked by Kita
The Snowtree cricket behaves in a rather interesting way: The rate at which it chirps depends linearly on the temperature. One summer evening you hear a cricket chirping at a rate of 160 chirps/minute, and you notice that the temperature is 80°F. Later in the evening, the cricket has slowed to 120 chirps/minute, and you notice that the temperature has dropped to 70°F. Express the temperature T as a linear function of the cricket's rate of chirping r.
Answers
Answered by
Reiny
treat it as two ordered pairs of the type (t,c)
given: (80,160) and (70, 120)
slope = (160-120)/(80-70) = 40/10 = 4
so
chirps = 4xtime + b
using (80,160)
160 = 4(80) + b
b = -160
chirps = 4(time) - 160
or
4(time) = chirps + 160
<b>time = (1/4)chirps + 40</b>
testing: if chirps = 120
time = (1/4)(120) + 40
= 30 + 40 = 70 , as given
given: (80,160) and (70, 120)
slope = (160-120)/(80-70) = 40/10 = 4
so
chirps = 4xtime + b
using (80,160)
160 = 4(80) + b
b = -160
chirps = 4(time) - 160
or
4(time) = chirps + 160
<b>time = (1/4)chirps + 40</b>
testing: if chirps = 120
time = (1/4)(120) + 40
= 30 + 40 = 70 , as given
Answered by
sPIHnsofLRH
Hello Philo !Je ne sais pas d'où viennent mes cercles à pâtisserie : mon frère me les a offerts pour mes 30 ans.En revanche, je sais où tu peux en trouver : chez Dehillerin, à Paris, pas très loin de Chttnele¢.SinoÃ, j'imagine que sur meilleurduchef il doivent en vendre.A bientôt !
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.