Asked by Anonymous
What volume of 0.0658 M calcium hydroxide is required to neutralize 45.10 mL of 0.0242 M nitric acid?
Answers
Answered by
bobpursley
the famous titration equation:
Na*volumeAcid=Nb*volumeBase
where N is concentration in Normality. Normality equals Molarity times Heq+.
Nitric acid HNO3 is ONE H+
Ca(OH)2 is TWO H+ equivalents
1*.0658 Va=2*.0242*.45.10 ml
solve for Va
Na*volumeAcid=Nb*volumeBase
where N is concentration in Normality. Normality equals Molarity times Heq+.
Nitric acid HNO3 is ONE H+
Ca(OH)2 is TWO H+ equivalents
1*.0658 Va=2*.0242*.45.10 ml
solve for Va
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