Question
Uniform Motion Related Problem
A car travelling at 60 kph left town at 9:00 a.m. Another car travelling at 65 kph left the same place half an hour later to overtake the first. At what time did the second car overtake the first?
A car travelling at 60 kph left town at 9:00 a.m. Another car travelling at 65 kph left the same place half an hour later to overtake the first. At what time did the second car overtake the first?
Answers
d1 = r1*t1 = 60km/h * 0.5h = 30 km after 0.5 h.
r2*t = r1*t + 30
65 * t = 60*t + 30
65t - 60t = 30
5t = 30
t = 6 hours.
r2*t = r1*t + 30
65 * t = 60*t + 30
65t - 60t = 30
5t = 30
t = 6 hours.
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