Asked by Krystal
Uniform Motion Related Problem
A car travelling at 60 kph left town at 9:00 a.m. Another car travelling at 65 kph left the same place half an hour later to overtake the first. At what time did the second car overtake the first?
A car travelling at 60 kph left town at 9:00 a.m. Another car travelling at 65 kph left the same place half an hour later to overtake the first. At what time did the second car overtake the first?
Answers
Answered by
Henry
d1 = r1*t1 = 60km/h * 0.5h = 30 km after 0.5 h.
r2*t = r1*t + 30
65 * t = 60*t + 30
65t - 60t = 30
5t = 30
t = 6 hours.
r2*t = r1*t + 30
65 * t = 60*t + 30
65t - 60t = 30
5t = 30
t = 6 hours.
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