Asked by Stacey
                If f (x)=x+2 , g(x)=-4x+3, and h(x)=x^2-2x+1, find each value.
1. (f x g x h) (3)
2. (h divided by fg) (-6)
3. [ g o ( h o f)] (-4)
If f(x)=5x , h(x)=x^2+6x+8 , solve f[h(a+4)]
            
            
        1. (f x g x h) (3)
2. (h divided by fg) (-6)
3. [ g o ( h o f)] (-4)
If f(x)=5x , h(x)=x^2+6x+8 , solve f[h(a+4)]
Answers
                    Answered by
            Steve
            
    I think you can easily fill in the first two. Simple multiplication and division, right?
(g◦(h◦f))(-4)
= g(h(f(-4)))
= g(h(-2))
= g(9)
= -33
Note that h(x) = (x-1)^2. So,
f(h(a+4))
= f((a+4-1)^2))
= f((a+3)^2)
= (a+3)^2+2
You can expand that if you want.
    
(g◦(h◦f))(-4)
= g(h(f(-4)))
= g(h(-2))
= g(9)
= -33
Note that h(x) = (x-1)^2. So,
f(h(a+4))
= f((a+4-1)^2))
= f((a+3)^2)
= (a+3)^2+2
You can expand that if you want.
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