Question
Hello! I'm having problems with these two math problems. I've tried to solve them but I got nowhere. If someone could please help me, that would great! Thanks again! :)
Directions: Verify the identity for each problem.
1.) cot^2y(sec^2-y-1)=1
2.) cosx+sin xtan x=sec x
Directions: Verify the identity for each problem.
1.) cot^2y(sec^2-y-1)=1
2.) cosx+sin xtan x=sec x
Answers
Reiny
The expression sec^2-y-1 makes no sense to me
is it sec^2 (-y-1) ?
#2
LS = cosx + sinx(sinx/cosx)
= (cos^2 x + sin^2 x)/cosx
= 1/cosx
= sec x
= RS
is it sec^2 (-y-1) ?
#2
LS = cosx + sinx(sinx/cosx)
= (cos^2 x + sin^2 x)/cosx
= 1/cosx
= sec x
= RS
Steve
I think that's just sec^2 y - 1, which is tan^2 y
cot^2 y * tan^2 y = 1
cot^2 y * tan^2 y = 1