Asked by Paige

Hello! I'm having problems with these two math problems. I've tried to solve them but I got nowhere. If someone could please help me, that would great! Thanks again! :)


Directions: Verify the identity for each problem.


1.) cot^2y(sec^2-y-1)=1

2.) cosx+sin xtan x=sec x

Answers

Answered by Reiny
The expression sec^2-y-1 makes no sense to me
is it sec^2 (-y-1) ?

#2
LS = cosx + sinx(sinx/cosx)
= (cos^2 x + sin^2 x)/cosx
= 1/cosx
= sec x
= RS
Answered by Steve
I think that's just sec^2 y - 1, which is tan^2 y

cot^2 y * tan^2 y = 1
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