Asked by Aiko
An automobile travels a distance of 12 km in 4 minutes. It then moves the next 12 km in 2 minutes. Please help me to calculate its acceleration which is constant throughout the motion. Thanks in advance ))))
Answers
Answered by
bobpursley
average velocity first=12/4 = 3km/min
average velocity second= 12/2=6km/min
accelaration=change velocity/time =3km/min /(6m)= .5 km/min^2
average velocity second= 12/2=6km/min
accelaration=change velocity/time =3km/min /(6m)= .5 km/min^2
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