Asked by george

The surface area, S, of a sphere of radius r feet is S = S(r) = 4πr2. Find the instantaneous rate of change of the surface area with respect to the radius r at r = 2. (4 points)
Answered by Steve
s = 4π r^2

ds/dr = 4π(2r) = 8πr
Answered by ash
64
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