Asked by Tammy
A 6090kg space probe mobing nose-first toward Jupiter at 105m/s relative to the Sun, fires its rocket engine ejecting 80 kg of exhaust at a speed of 253 m/s relative to the space probe. What is the final velocity of the probe?
I should have gotten 108m/s Can you show me the correct way to solve this problem? Thanks so much for your time and effort. I really would apprecitate it!
Momentum:
80(253)=(6090-80)delta v
deltav=?
This is an approximation. A better solution is to take the average mass of the spacecraft as (6090-80/4), but it wont matter much.
There is an exact method in Calculus, but I assume you are not a calculus person.
I should have gotten 108m/s Can you show me the correct way to solve this problem? Thanks so much for your time and effort. I really would apprecitate it!
Momentum:
80(253)=(6090-80)delta v
deltav=?
This is an approximation. A better solution is to take the average mass of the spacecraft as (6090-80/4), but it wont matter much.
There is an exact method in Calculus, but I assume you are not a calculus person.
Answers
Answered by
George
Conservation of momentum:
6090(105) = 80(-253) + 6010(Vf)
Vf = 109.77 m/s
6090(105) = 80(-253) + 6010(Vf)
Vf = 109.77 m/s
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