Asked by cracra
Plz help me????? Carter left Town A at noon, driving toward Town B at an average speed of 50 mph. At 12:30 P.M., Max headed from Town B to Town A along the same road. At 3 P.M., they met each other along the way, and Carter realized that he had completed 60% of his journey.
A:How far was Town A from Town B?
B:At what speed was Max traveling?
A:How far was Town A from Town B?
B:At what speed was Max traveling?
Answers
Answered by
cracra
plz help i really need help
Answered by
Steve
what you really need is to think about the problem.
By 12:30, car A had been traveling 1/2 hr at 50 mph. SO, it had gone 25 miles.
At 3:PM, both cars had been traveling an additional 2.5 hours, so Carter had gone another 2.5*50 = 125 miles.
Carter's total distance is thus 150 miles.
So, 150 is 60% of the distance.
150/.6 = 250 miles.
So, A is 250 miles from B.
Max took 2.5 hours to travel the other 100 miles, so he was going at 100/2.5 = 40 mph.
All you have to do to solve word problems is take each fact and write it as math.
By 12:30, car A had been traveling 1/2 hr at 50 mph. SO, it had gone 25 miles.
At 3:PM, both cars had been traveling an additional 2.5 hours, so Carter had gone another 2.5*50 = 125 miles.
Carter's total distance is thus 150 miles.
So, 150 is 60% of the distance.
150/.6 = 250 miles.
So, A is 250 miles from B.
Max took 2.5 hours to travel the other 100 miles, so he was going at 100/2.5 = 40 mph.
All you have to do to solve word problems is take each fact and write it as math.
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