Question
A sled weighing 200.0 N is pulled along a horizontal surface with a horizontal force of 45 N. The coefficient of static friction is 0.65 and of kinetic friction is 0.40. What is the force of friction?
So I got Ff=200*.4= 80N
So I got Ff=200*.4= 80N
Answers
Damon
If the velocity is constant you are correct.
Angel
Thanks Damonnn:)
Damon
You are welcome.