Asked by Wing
How about this.
One bad contains 4 white balls and 6 black balls. Another bag contains 8 white balls and 2 black balls. A coin tossed to select a bad, then a ball is randomly selected from that bag.
a. What is the probability that a white ball will be drawn?
b. Suppose a white ball is drawn. What is the probability that it came from the First Bag?
Thanks
THE ANS : A>3/5
B>1/3
But how do you get those?
One bad contains 4 white balls and 6 black balls. Another bag contains 8 white balls and 2 black balls. A coin tossed to select a bad, then a ball is randomly selected from that bag.
a. What is the probability that a white ball will be drawn?
b. Suppose a white ball is drawn. What is the probability that it came from the First Bag?
Thanks
THE ANS : A>3/5
B>1/3
But how do you get those?
Answers
Answered by
Writeacher
http://www.jiskha.com/display.cgi?id=1217983092
Use the ideas in Reiny's post; adjust for the numbers you're now posting.
Use the ideas in Reiny's post; adjust for the numbers you're now posting.
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