Asked by Billiam
An observer stands 25 feet from the base of a 50 foot flagpole and watches a flag being lowered at a rate of 5 ft/sec. Determine the rare at which the angle of elevation from the observer to the flag is changing at the instant that the flag is 25 ft.
Keep getting like .1 or .2, help apreciated
Keep getting like .1 or .2, help apreciated
Answers
Answered by
Damon
elevation angle A = 45 degrees = pi/4 radians
tan A = h/25
d tan A/dA = sec^2 A = (1/25) dh/dA
so
25 sec^2 A * dA/dt= dh/dt = 5
dA/dt = (1/5) cos^2 A
but cos^2 A = 1/2
dA/dt = .1 radians/second
So I agrees
but maybe you want degrees?
.1 Rad/s( 180 deg/rad) = 18 degrees/second
tan A = h/25
d tan A/dA = sec^2 A = (1/25) dh/dA
so
25 sec^2 A * dA/dt= dh/dt = 5
dA/dt = (1/5) cos^2 A
but cos^2 A = 1/2
dA/dt = .1 radians/second
So I agrees
but maybe you want degrees?
.1 Rad/s( 180 deg/rad) = 18 degrees/second
Answered by
Billiam
oh its in radians
thanks a bunch, makes more sense :D
thanks a bunch, makes more sense :D
Answered by
Damon
You are welcome ;)
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