Asked by kennedy
A bag contains the following marbles:6 red,4 orange,3 yellow,2 blue and 5 green. You choose a marble at random and do not replace it. Then you select another marble.
P(red,then blue)3/95
P(orange,then blue) 2/95
P(blue,then yellow) 3/190
P(red,then yellow) 9/190
P(blue,then green) 1/38
P(Red,then red)9/95
P(red,then blue)3/95
P(orange,then blue) 2/95
P(blue,then yellow) 3/190
P(red,then yellow) 9/190
P(blue,then green) 1/38
P(Red,then red)9/95
Answers
Answered by
PsyDAG
P(red, blue) = 6/20 * 2/19 = 12/380 =3/95
P(blue, Yellow) = 2/20 * 3/19 = 6/380 = 3/190
I only checked two, but if you did the same process and your math is correct, they should all be right.
P(blue, Yellow) = 2/20 * 3/19 = 6/380 = 3/190
I only checked two, but if you did the same process and your math is correct, they should all be right.
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