Asked by HELP!
Someone bought 7 ears of corn and 6 oranges for $3.66. At the same time a second person bought 10 ears of corn and 3 oranges for $3.39. Find the price of each.
Answer: oranges would be .78 cents and corn would be .41 cents each
Answer: oranges would be .78 cents and corn would be .41 cents each
Answers
Answered by
Reiny
You could have easily checked your answer by replacing them in the original question.
here is what I did:
7c + 6o = 366 , I will work in cents
10c + 3o = 339
double the 2nd:
20c + 6o = 678
7c + 6o = 366
subtract them:
13c = 312
c = 24
back into 1st:
7c + 6o = 366
7(24) + 6o = 366
168 + 6o = 366
6o = 198
o = 33
oranges cost 33 cents and corn costs 24 cents
check"
7(24) + 6(33) = 366 , check!
10(24) + 3(33) = 339, check!
do your previous questions the same way
here is what I did:
7c + 6o = 366 , I will work in cents
10c + 3o = 339
double the 2nd:
20c + 6o = 678
7c + 6o = 366
subtract them:
13c = 312
c = 24
back into 1st:
7c + 6o = 366
7(24) + 6o = 366
168 + 6o = 366
6o = 198
o = 33
oranges cost 33 cents and corn costs 24 cents
check"
7(24) + 6(33) = 366 , check!
10(24) + 3(33) = 339, check!
do your previous questions the same way
Answered by
Anonymous
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