Question

Given that k,3k and k+1 are three consecutive terms of an A.P,find the numerical value of k.Then find the first term if 3k is the sixth term of the progression.
Answer:k=1over4
a=-7over4
I got the k but the a i can't get

Answer 1

first condition:
3k - k = k+1 - 3k
4k = 1
k = 1/4, you had that

so we have
*, *, *, *, k , 3k, k+1

a+5d = 3k = 3/4
a + 4d = k = 1/4
subtract them
d = 1/2

in a+4d = 1/4
a + 2 = 1/4
a = 1/4-2 = -7/4

Answer 2

Thank you..