Asked by Anonymous
1. Find all critical values for f(x)=(9-x^2)^⅗
A. 0
B. 3
C. -3,3
D. -3, 0, 3
E. none of these
I got D. I found the derivative and solved for critical numbers.
2. Find all intervals on which the graph of f(x)=(x-1)/(x+3) is concave upward
A. (negative infinity, infinity)
B. (negative infinity, -3)
C. (1, infinity)
D. (-3, infinity)
E. none of these
I got B. I found the first derivative. I found the second derivative. Then used the interval test to determine concavity.
3. Given f(x)=10-(16/x), find all c in the interval [2,8] that satisfies the Mean Value Theorem.
A. 4
B. 5
C. 8/5
D. + or - 4
E. none of these
I got A. I found f(2) and f(8) and used the MVT. I found the derivative of the function and plugged in c for x. I solved for c. And made sure answer was in the interval.
Thank you for checking my answers.
A. 0
B. 3
C. -3,3
D. -3, 0, 3
E. none of these
I got D. I found the derivative and solved for critical numbers.
2. Find all intervals on which the graph of f(x)=(x-1)/(x+3) is concave upward
A. (negative infinity, infinity)
B. (negative infinity, -3)
C. (1, infinity)
D. (-3, infinity)
E. none of these
I got B. I found the first derivative. I found the second derivative. Then used the interval test to determine concavity.
3. Given f(x)=10-(16/x), find all c in the interval [2,8] that satisfies the Mean Value Theorem.
A. 4
B. 5
C. 8/5
D. + or - 4
E. none of these
I got A. I found f(2) and f(8) and used the MVT. I found the derivative of the function and plugged in c for x. I solved for c. And made sure answer was in the interval.
Thank you for checking my answers.
Answers
Answered by
Steve
#1,2 are ok
#3:
f' = 16/x^2
16/x^2 = (8-2)/6 = 1
x^2=16
x=4 in [2,8]
So, (A) is correct
#3:
f' = 16/x^2
16/x^2 = (8-2)/6 = 1
x^2=16
x=4 in [2,8]
So, (A) is correct
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.