the top factors, so
f(x) = (x+1)(x+3)(x+4)/(x+4)
= x^2 + 4x + 3 , x ≠ -4
f ' (x) = 2x + 4
= 0 for a max/min
2x + 4 = 0
x = -2
Since the function is basically the parabola
y = x^2 + 4x + 3 , with a hole at (-4,3)
which opens up,
x = -2 will produce a minimum
f(-2) = 4 - 8 + 3 = -1
so (-2,-1) is a minimum
choice A looks good
Find the absolute maximum and absolute minimum of f on the interval (-4, -1]:
f(x)=(x^3+8x^2+19x+12)/(x+4)
A. Maximum: None; Minimum: (-2, -1)
B. Maximum: (-4, 3); Minimum (-1, 0)
C. Maximum: (-4, 3); Minimum: (-2, -1)
D. Maximum: None; Minimum: (-1, 0)
E. none of these
1 answer
0 answers