Asked by slomo

I need to be shown the steps on how you derive at this answer

(5a^7 / 2b^5c)^0 = 1

Answers

Answered by Damon
ANYTHING^0 = 1

no more steps needed
Answered by Damon
here, for any old x
x^0 * x^1 = x^(1+0) = x^1
so
x^0 was 1
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