Asked by sarth
factorise4(x-y)^3-(x-y)
Answers
Answered by
Steve
factor out the (x-y):
(x-y)(4(x-y)^2-1)
Now you have a difference of squares:
(x-y)(2(x-y)+1)(2(x-y)-1)
...
(x-y)(4(x-y)^2-1)
Now you have a difference of squares:
(x-y)(2(x-y)+1)(2(x-y)-1)
...
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