q1 = heat removed in changing T from steam at 122 to steam at 100.
q1 = mass steam x specific heat steam x (Tfinal-Tinitial)
q2 = heat removed on condensation at 100 C to water at 100 C.
q2 = mass steam x delat H(heat condensation)
q3 = heat removed in changing T of liquid water from 100 C to 0 C.
q3 = mass H2O x specific heat H2O x (Tfinal-Tinitial)
q4 = heat removed on freezing liquid water at 0C to solid ice at 0C.
q4 = mass H2O x delta H fusion.
Total is q1 + q2 + q3 + q4.
A quantity of steam (750 g) at 122°C is condensed, and the resulting water is frozen into ice at 0°C. How much heat was removed?
1 answer
1 answer