How many positive factors does

62x(63^3+63^2+63+1)+1 have?

(With explanatio pls... Tnx)

2 answers

63^3+63^2+63+1 = (63^4-1)/(63-1) = 63^4-1
So, your number is

63^4-1+1 = 63^4 = 3^8 * 7^4

So, the prime factors are 3 and 7

I'll leave it to you to determine how many factors there are in all
Tnx... But where did exponent 4 and minus one come from?
Similar Questions
  1. Consider the problem.−38×−123 Determine the sign of the product. (1 point) Responses Positive - If the signs of the factors
    1. answers icon 1 answer
    1. answers icon 1 answer
  2. 1 of 161 of 16 ItemsQuestion 1 Consider the problem. −38×−123 Determine the sign of the product. (1 point) Responses
    1. answers icon 1 answer
  3. 1 of 161 of 16 ItemsQuestion 1 Consider the problem. −38×−123 Determine the sign of the product. (1 point) Responses
    1. answers icon 1 answer
more similar questions