Asked by Math

How many positive factors does
62x(63^3+63^2+63+1)+1 have?

(With explanatio pls... Tnx)
Answered by Steve
63^3+63^2+63+1 = (63^4-1)/(63-1) = 63^4-1
So, your number is

63^4-1+1 = 63^4 = 3^8 * 7^4

So, the prime factors are 3 and 7

I'll leave it to you to determine how many factors there are in all
Answered by Math
Tnx... But where did exponent 4 and minus one come from?
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