let the smaller angle be x°
then the larger is 7x + 10
but ...
x + 7x + 10 = 180
take over
two complementary angles are drawn such that one angle is 10° more than seven times the other angle find the measur of each angle
8 answers
I believe the angles should sum to 90°
Thanks for the correction , Steve
7493h
jpkkjk,;
the answer is 27
jpkkjk,;
the answer is 27
Let y° is the smallest angel Y° +7y°+ 10°=90° 8y°+10°=90° 8y°=90°_10°. 8y°=80° =10°
Ow thanks
but what is the correct answer?😮😞
abebe or sophoniyas?
but what is the correct answer?😮😞
abebe or sophoniyas?
Y=10
X+7x+10=90
8x+10=90
8x=90-10
8x\8=80\8
X=10
Y=7(10+10)
Y=70+10
Y=80
8x+10=90
8x=90-10
8x\8=80\8
X=10
Y=7(10+10)
Y=70+10
Y=80