Asked by abebe

two complementary angles are drawn such that one angle is 10° more than seven times the other angle find the measur of each angle
Answered by Reiny
let the smaller angle be x°
then the larger is 7x + 10

but ...
x + 7x + 10 = 180

take over
Answered by Steve
I believe the angles should sum to 90°
Answered by Reiny
Thanks for the correction , Steve
Answered by sofoniyas
7493h
jpkkjk,;
the answer is 27
Answered by Anonymous
Let y° is the smallest angel Y° +7y°+ 10°=90° 8y°+10°=90° 8y°=90°_10°. 8y°=80° =10°
Answered by rekik
Ow thanks
but what is the correct answer?😮😞
abebe or sophoniyas?
Answered by Corona
Y=10
Answered by Anonymous
X+7x+10=90
8x+10=90
8x=90-10
8x\8=80\8
X=10

Y=7(10+10)
Y=70+10
Y=80
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