Asked by Sunflower
(x^4y^6z^12/9^-2x^3y^-8z^-9)^0
Answers
Answered by
drwls
Is the ^ supposed to represent that what follows is an exponent? You have exponents added on top of exponents.
Since the whole thing is raised to the zero power, the result is 1, no matter what x, y and z are.
A trick question, perhaps.
Since the whole thing is raised to the zero power, the result is 1, no matter what x, y and z are.
A trick question, perhaps.
Answered by
Sunflower
This is what the professor gave use to do. Is there anyway you can so me how you got 1?
Answered by
drwls
Any number to the zero power is 1.
Why? Because for ANY number N
N / N = 1 = N^1 * N*-1 = N^0
Why? Because for ANY number N
N / N = 1 = N^1 * N*-1 = N^0
Answered by
Sunflower
thanks
Answered by
DrBob222
Any number raised to the zero power is 1.
50,000^0 = 1.
6,245^0 = 1
Try seeing it this way.
X^3*X^-3 = X<sup>3-3</sup> = X<sup>0</sup> but
X^3*X^-3 = X^3/X3 = 1; therefore, it follows that X<sup>0</sup> = 1
50,000^0 = 1.
6,245^0 = 1
Try seeing it this way.
X^3*X^-3 = X<sup>3-3</sup> = X<sup>0</sup> but
X^3*X^-3 = X^3/X3 = 1; therefore, it follows that X<sup>0</sup> = 1
Answered by
DrBob222
I made a typo in the last line.
X^3*X^-3 = X^3/X^3 = 1; therefore, ....
X^3*X^-3 = X^3/X^3 = 1; therefore, ....
Answered by
Anonymous
question 1
(3y- 5)/8(9y + 4)/16 = 0
solve the equation
5.5(25y-20.3) = 5.6x-20.3
(3y- 5)/8(9y + 4)/16 = 0
solve the equation
5.5(25y-20.3) = 5.6x-20.3
Answered by
drwls
"question 1" looks like two questions. The first one needs more parentheses to explain the order of operations. The second one cannot be solved becasue it contains two variables.
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