Asked by Ava
A box is pulled along a level floor at a constant speed by a rope that makes a 45 degree angle with the floor. The box weighs 100N. The coefficient of sliding friction is 0.75. The normal force exerted on the box by the floor is?
Answers
Answered by
Henry
M*g = 100 N.
Fn = 100*Cos0 - Fap*sin45 = Normal force
Fn = 100 - 0.707Fap
Fk=u*Fn = 0.75(100-0.707Fap)=75-0.53Fap
Fap-Fk = M*a
Fap-75 + 0.53Fap = M*0 = 0
1.53Fap = 75
Fap = 49 N. = Force applied.
Fn = 100-0.707Fap = 100 - 0.707*49 = 65.4 N. = Normal force.
Fn = 100*Cos0 - Fap*sin45 = Normal force
Fn = 100 - 0.707Fap
Fk=u*Fn = 0.75(100-0.707Fap)=75-0.53Fap
Fap-Fk = M*a
Fap-75 + 0.53Fap = M*0 = 0
1.53Fap = 75
Fap = 49 N. = Force applied.
Fn = 100-0.707Fap = 100 - 0.707*49 = 65.4 N. = Normal force.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.