Asked by Ava

A box is pulled along a level floor at a constant speed by a rope that makes a 45 degree angle with the floor. The box weighs 100N. The coefficient of sliding friction is 0.75. The normal force exerted on the box by the floor is?

Answers

Answered by Henry
M*g = 100 N.

Fn = 100*Cos0 - Fap*sin45 = Normal force
Fn = 100 - 0.707Fap

Fk=u*Fn = 0.75(100-0.707Fap)=75-0.53Fap

Fap-Fk = M*a
Fap-75 + 0.53Fap = M*0 = 0
1.53Fap = 75
Fap = 49 N. = Force applied.

Fn = 100-0.707Fap = 100 - 0.707*49 = 65.4 N. = Normal force.

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