Question

The coefficient of friction sliding on wood is 0.30. The force needed to slide a wooden block weighing 500N across a horizontal surface is:

a. 50N
b. 150N
c. 300N
d. 500N

Answer 1

M*g = 500 N. = Normal force(Fn).

Fk = u*Fn = 0.3 * 500 = 150 N. = Force of kinetic friction.

Fap-Fk = M*a
Fap-150 = M*0 = 0
Fap = 150 N. = Force applied.

Answer 2

Ali